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Physics · Fluids

Terminal Velocity Calculator

Find the steady fall speed where air drag balances gravity.

kg
The falling object’s mass.
Frontal area facing the airflow.
Shape factor, dimensionless.
kg/m³
1.225 kg/m³ at sea level.
Typical shapes — tap to load
Terminal velocity (v_t)
42.78m/s

≈ 154.02 km/h — the steady speed where air drag balances gravity.

Terminal velocity vs mass (rises with the square root of mass)
Terminal velocity rising with the square root of mass for fixed area, drag, and air density60.51 m/s0 m/s0 kg160 kg

Terminal velocity is the constant speed a falling object reaches when air drag balances gravity, given by v_t = √(2mg ÷ (ρ·A·C_d)). A belly-down skydiver (80 kg, A ≈ 0.7 m², C_d ≈ 1.0, ρ = 1.225 kg/m³) reaches about 43 m/s — roughly 154 km/h.

What terminal velocity is

As an object falls, gravity pulls it down while air pushes back with a drag force that grows with the square of speed. At first the object accelerates, but the faster it goes the harder the air resists. Eventually drag exactly cancels the weight, the net force reaches zero, and the object stops speeding up — it has hit its terminal velocity and falls at a steady rate for the rest of the drop.

Because drag depends on the object’s shape and the air it moves through, terminal velocity is not a single number. It rises with heavier mass and falls with larger frontal area, a higher drag coefficient, or denser air — which is why a skydiver, a feather, and a raindrop each settle at very different speeds.

v_t = √(2mg ÷ (ρ · A · C_d))

m = mass (kg), g = 9.81 m/s², ρ = air density (1.225 kg/m³ at sea level), A = cross-sectional area (m²), C_d = drag coefficient (dimensionless)

Worked example

A skydiver in the belly-down (spread-eagle) position: m = 80 kg, A = 0.7 m², C_d = 1.0, ρ = 1.225 kg/m³, g = 9.81 m/s².

  1. 1
    Gather the inputs. m = 80 kg, A = 0.7 m², C_d = 1.0, ρ = 1.225 kg/m³, and g = 9.81 m/s².
  2. 2
    Multiply out the numerator. 2 × m × g = 2 × 80 × 9.81 = 1569.6.
  3. 3
    Multiply out the denominator. ρ × A × C_d = 1.225 × 0.7 × 1.0 = 0.8575.
  4. 4
    Divide, then take the square root. v_t = √(1569.6 ÷ 0.8575) = √1830.4 ≈ 42.78 m/s.
  5. 5
    Convert to km/h. 42.78 m/s × 3.6 ≈ 154 km/h.

Typical drag coefficients

Approximate C_d values for common shapes moving through air; real values vary with speed and surface.

ShapeDrag coefficient (C_d)
Flat plate (face-on)~1.28
Skydiver (belly-down)~1.0
Smooth sphere~0.47
Modern car~0.3
Streamlined / teardrop body~0.04

Reading the result

Terminal velocity is reached only when drag balances gravity. Before that point the object is still accelerating, so this speed is a ceiling, not the speed at every instant of the fall. A short drop may never get close to it.

Posture and area matter enormously. A skydiver who pulls into a head-down dive shrinks A and C_d, and terminal velocity can more than double to over 90 m/s; opening a parachute multiplies A dozens of times and drops it to a survivable few m/s. Thinner air at altitude (lower ρ) also raises terminal velocity, which is why high-altitude jumps start faster.

What is a drag coefficient?
The drag coefficient C_d is a dimensionless number that captures how streamlined a shape is. A flat plate is about 1.28, a sphere about 0.47, and a teardrop as low as 0.04. A higher C_d means more air resistance and therefore a lower terminal velocity.
How does body position change terminal velocity?
Position changes both the frontal area A and the drag coefficient C_d. A belly-down skydiver (large A) falls near 55 m/s, while a head-down, arms-back dive shrinks A and streamlines the body, pushing terminal velocity past 90 m/s.
Why doesn’t terminal velocity depend on how high you fall from?
Terminal velocity is set by the balance of drag and weight, not by drop height. Height only decides whether the object has enough distance to reach that steady speed — a very short fall may end before drag ever catches up with gravity.
Does a heavier object have a higher terminal velocity?
Yes, if its shape and size stay the same. Terminal velocity scales with the square root of mass, so doubling the mass raises it by about 41%. That is why a dense compact object falls faster than a light one of the same shape.
What air density should I use?
Use ρ = 1.225 kg/m³ for standard air at sea level and 15 °C. Air thins with altitude — roughly 1.0 kg/m³ at 2 km and 0.7 kg/m³ at 5 km — so terminal velocity is higher up high, which the calculator reflects when you lower ρ.
Does this formula work in water or other fluids?
Yes. The same equation applies to any fluid; just replace ρ with the fluid’s density. Water is about 1000 kg/m³ — roughly 800 times denser than air — so terminal velocities in water are far lower for the same object.