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Physics · Mechanics

Kinematics Solver

From initial velocity, acceleration, and time, get final velocity and displacement.

m/s
m/s²
s
Example motions — tap to load
Final velocity (v)
29.43m/s

Displacement (s): 44.145 m

Velocity–time graph — the slope is the acceleration, the area under it is the displacement
Velocity–time line rising from 0 to 29.43 metres per second as acceleration acts over 3 seconds29.43 m/s0 m/s0 s3 s

With constant acceleration, use v = u + at and s = ut + ½at². For an object dropped from rest (u = 0) for t = 3 s at a = 9.81 m/s², the final velocity is 0 + 9.81 × 3 = 29.43 m/s and it falls 44.145 m.

The equations of motion

When acceleration is constant, motion is fully described by five quantities — collectively called SUVAT. Knowing any three of them lets you solve for the rest. This tool starts from initial velocity (u), acceleration (a), and time (t), then gives you the final velocity and displacement. To find the force behind that acceleration, pair it with the force calculator (F = ma).

v = u + at  ·  s = ut + ½at²

u = initial velocity, v = final velocity, a = acceleration, t = time, s = displacement

Worked example

An object dropped from rest (u = 0) falls for t = 3 s with a = 9.81 m/s²:

  1. 1
    Find the final velocity. v = u + at = 0 + 9.81 × 3 = 29.43 m/s.
  2. 2
    Set up the displacement equation. s = ut + ½at² = 0 × 3 + ½ × 9.81 × 3² = 0 + ½ × 9.81 × 9.
  3. 3
    Compute the displacement. ½ × 9.81 × 9 = 44.145 m fallen in those 3 seconds.

The five SUVAT variables

Pick a consistent positive direction; all five share the same SI units below.

SymbolQuantitySI unit
sDisplacementmetre (m)
uInitial velocitym/s
vFinal velocitym/s
aAccelerationm/s²
tTimesecond (s)

Sign conventions and assumptions

Choose a positive direction and keep it. If you call “up” positive, then gravity is a = −9.81 m/s². A deceleration is simply a negative acceleration — there is no separate equation for it.

Acceleration must be constant. The SUVAT equations break down the moment acceleration changes mid-motion; for that you need calculus or piecewise segments.

Common mistake: forgetting to square the time in ½at². Squaring before multiplying is what makes displacement grow so quickly as time passes.

What is SUVAT?
The five kinematic variables for constant acceleration: s (displacement), u (initial velocity), v (final velocity), a (acceleration), t (time). Know any three and you can solve for the rest.
Does this assume constant acceleration?
Yes — the SUVAT equations only apply to uniform (constant) acceleration. If the acceleration changes during the motion, split it into segments or use calculus.
Can I model free fall with it?
Yes. Set acceleration to g ≈ 9.81 m/s² (downward). Drop from rest means u = 0; throw downward means u is your launch speed.
How do I handle deceleration?
Enter the acceleration as a negative number relative to your chosen positive direction. A car braking at 4 m/s² in the +x direction has a = −4 m/s².
What if I don’t know the time?
Use the timeless equation v² = u² + 2as instead, which avoids t entirely. This tool starts from t, so derive it from another pair first.
Why is time squared in s = ut + ½at²?
Displacement under constant acceleration grows with the square of time, so the ½at² term must square t before multiplying. Forgetting to square it is the most common mistake — at t = 3 s with a = 9.81, that term is ½ × 9.81 × 9 = 44.145 m, not ½ × 9.81 × 3.