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Decibel Calculator

Convert a power or amplitude ratio to decibels and back, or add several sound levels together.

Mode
Quantity
×
How many times larger the power is. 2 means double the power.
Level
3.01dB

A decibel measures a ratio on a logarithmic scale. For power, dB = 10·log₁₀(P₁ ÷ P₂); for amplitude, voltage, or pressure, dB = 20·log₁₀(V₁ ÷ V₂). Doubling power is 10·log₁₀(2) = +3.01 dB, while doubling amplitude is 20·log₁₀(2) = +6.02 dB.

What a decibel is

A decibel (dB) is not an absolute unit like a metre or a volt — it expresses how much bigger one quantity is than a reference, compressed onto a logarithmic scale so that huge ranges fit into small numbers. Because our ears and many instruments respond to ratios rather than absolute differences, the log scale matches how loudness and signal strength are actually perceived.

The catch is the factor out front. When you compare power quantities (watts, acoustic intensity) you multiply the log by 10. When you compare amplitude quantities (voltage, sound pressure, signal level) you multiply by 20, because power is proportional to amplitude squared and log(x²) = 2·log(x). That single factor is why doubling power adds 3 dB but doubling amplitude adds 6 dB.

dB SPL is a special case: sound pressure level measured against the threshold of hearing (20 µPa). Everyday values run from a 30 dB whisper to a 110 dB concert. Because dB SPL is a power-like measure of intensity, incoherent sources add by summing their power ratios, not their decibel numbers.

dB = 10·log₁₀(P₁ ÷ P₂) = 20·log₁₀(V₁ ÷ V₂)

Use 10 for power ratios (watts, intensity); use 20 for amplitude ratios (voltage, pressure). To combine incoherent sound levels: total = 10·log₁₀( Σ 10^(Lᵢ ÷ 10) ).

Worked example

An amplifier doubles the acoustic power of a speaker. How many decibels louder is that in power terms?

  1. 1
    Pick power or amplitude. Power ratios use the factor 10; amplitude, voltage, and pressure ratios use 20. Here we are doubling power, so the factor is 10.
  2. 2
    Write the ratio. Double the power means P₁ ÷ P₂ = 2.
  3. 3
    Take the base-10 logarithm. log₁₀(2) = 0.30103.
  4. 4
    Multiply by the factor. 10 × 0.30103 = 3.01 dB, so doubling power is about +3 dB.
  5. 5
    Compare with amplitude. Doubling amplitude instead would be 20 × 0.30103 = 6.02 dB.

Common decibel changes

How familiar ratios translate into decibels, using 10·log for power and 20·log for amplitude.

ChangeDecibelsWhy
Double the power+3.01 dB10·log₁₀(2)
Double the amplitude / voltage+6.02 dB20·log₁₀(2)
Ten times the power+10 dB10·log₁₀(10) — roughly 2× as loud
Ten times the amplitude+20 dB20·log₁₀(10)
Halve the power−3.01 dB10·log₁₀(0.5)

Typical sound levels (dB SPL)

Approximate everyday sound pressure levels for reference.

SourceLevel
Whisper30 dB
Normal conversation60 dB
Busy traffic80 dB
Rock concert110 dB

Adding decibels correctly

You cannot simply add two decibel numbers — 60 dB plus 60 dB is not 120 dB. Because decibels are logarithmic, you convert each level back to a linear power ratio, add those, then convert to decibels again. Two equal incoherent sources of 60 dB give 10·log₁₀(10⁶ + 10⁶) = 63.01 dB — a rise of just about 3 dB, the same +3 dB you get from doubling any power. Ten equal sources add 10 dB, not ten times the level. This only holds for incoherent sources; correlated signals can add in amplitude and climb faster.

Why is doubling power only +3 dB?
Because decibels are logarithmic: for power, dB = 10·log₁₀(ratio). Doubling gives 10·log₁₀(2) = 10 × 0.30103 = 3.01 dB. The scale compresses ratios, so each further doubling adds another 3 dB rather than stacking linearly.
What is the difference between the power and amplitude formulas?
Power quantities (watts, acoustic intensity) use 10·log₁₀(ratio); amplitude quantities (voltage, sound pressure, signal level) use 20·log₁₀(ratio). The 20 appears because power is proportional to amplitude squared, and log(x²) = 2·log(x). That is why doubling amplitude is +6.02 dB but doubling power is +3.01 dB.
How do I add two dB levels together?
Do not add the decibel numbers directly. Convert each to a power ratio with 10^(L ÷ 10), sum those ratios, then take 10·log₁₀ of the total. For 60 dB + 60 dB: 10⁶ + 10⁶ = 2×10⁶, and 10·log₁₀(2×10⁶) = 63.01 dB.
Why do two equal sources add only 3 dB?
Two equal incoherent sources double the total power, and doubling power is 10·log₁₀(2) = 3.01 dB. So 60 dB and 60 dB combine to about 63 dB, not 120 dB. Adding a source much quieter than another barely changes the total at all.
How many decibels is “twice as loud”?
Perceived loudness roughly doubles every +10 dB, which corresponds to ten times the power. A +3 dB change doubles the power but is only a modest, clearly audible increase — not a doubling of loudness. This is a perceptual rule of thumb, not an exact physical law.
Can decibels be negative?
Yes. A ratio below 1 gives a negative decibel value: halving power is 10·log₁₀(0.5) = −3.01 dB, and a signal a tenth as strong is −10 dB. Negative simply means the quantity is smaller than the reference. The logarithm is undefined only for zero or negative ratios.
What reference does dB SPL use?
Sound pressure level is measured against 20 µPa, the nominal threshold of human hearing. Because pressure is an amplitude quantity, dB SPL uses 20·log₁₀(p ÷ 20 µPa). A whisper sits near 30 dB SPL and a rock concert near 110 dB SPL.