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Engineering · Materials

Thermal Expansion Calculator

Find how much a part grows or shrinks with temperature using ΔL = α · L₀ · ΔT.

MaterialSets the linear expansion coefficient α.
×10⁻⁶/°C
Steel (mild): fixed value.
m
Length before heating or cooling.
°C
Positive warms and expands; negative cools and contracts.
Try a scenario
Change in length (ΔL)
6mm

ΔL = α × L₀ × ΔT = 0.006 m. Final length = 10.006 m (ΔT = 50 °C).

10.006
final length (m)
0.12
area ΔA/A₀ ≈ 2αΔT (%)
0.18
volume ΔV/V₀ ≈ 3αΔT (%)

Linear thermal expansion is ΔL = α · L₀ · ΔT — the expansion coefficient times the original length times the temperature change. A 10 m steel beam (α = 12×10⁻⁶ /°C) warmed by 50 °C grows ΔL = 12×10⁻⁶ × 10 × 50 = 0.006 m = 6 mm, so its final length is 10.006 m.

Why materials expand when heated

Heating a solid makes its atoms vibrate harder and sit a little farther apart, so the whole object grows; cooling reverses it. The coefficient of linear thermal expansion (α) captures how strongly a given material responds — it is the fractional change in length per degree, so its units are per °C (identical in size to per kelvin, since a one-degree change is the same on both scales). Metals like aluminum expand a lot; special alloys like Invar barely move at all.

Expansion happens in every direction. Linear expansion tracks one dimension (length). Area expansion tracks a surface and grows with a coefficient of roughly 2α, while volumetric expansion tracks the whole solid with roughly 3α. Those factors of 2 and 3 come straight from squaring and cubing a length that has each grown by the same small fraction.

ΔL = α · L₀ · ΔT  ·  L = L₀ + ΔL

ΔL = change in length (m), α = linear expansion coefficient (per °C), L₀ = original length (m), ΔT = temperature change (°C)

Worked example

A 10 m mild-steel beam (α = 12×10⁻⁶ /°C) heats from 20 °C to 70 °C. Find how much it lengthens and its final length.

  1. 1
    Look up the expansion coefficient. Mild steel has α = 12×10⁻⁶ /°C — a fractional stretch of 0.000012 per degree.
  2. 2
    Find the temperature change ΔT. ΔT = 70 °C − 20 °C = 50 °C. A ΔT in °C equals the same ΔT in kelvin.
  3. 3
    Apply ΔL = α · L₀ · ΔT. ΔL = 12×10⁻⁶ × 10 m × 50 °C = 0.006 m = 6 mm.
  4. 4
    Add it to the original length. L = L₀ + ΔL = 10 + 0.006 = 10.006 m.
  5. 5
    Scale up for area or volume if needed. Area change ≈ 2αΔT and volume change ≈ 3αΔT, here 0.12% and 0.18% of the original.

Linear expansion coefficients (α)

Typical values near room temperature, in ×10⁻⁶ per °C. Values vary a little with grade and temperature range.

Materialα (×10⁻⁶ /°C)Note
Aluminum23Expands the most of the common metals
Gold14Soft, dense metal
Copper17Common in pipes and wiring
Stainless steel17Higher than mild steel
Steel (mild)12Reference structural value
Iron12Similar to mild steel
Concrete12Close to steel — why reinforcement works
Glass (ordinary)9Low; borosilicate is lower still
Invar1.2Nickel–iron alloy made to barely expand

Where this matters: expansion joints and rail gaps

Because a long structure can move by millimetres or centimetres across a hot summer day, engineers design the movement in rather than fight it. Bridges sit on expansion joints and sliding bearings so the deck can grow without buckling or cracking its supports. Railway tracks traditionally left small gaps between rails — the source of the classic clickety-clack — and modern continuous welded rail is instead pre-stressed and heavily anchored so it cannot buckle. Pipelines use expansion loops for the same reason.

Matched coefficients matter too: reinforced concrete works partly because steel and concrete expand at almost the same rate (both about 12×10⁻⁶ /°C), so they stay bonded through temperature swings. When two joined materials have very different coefficients — a reason Invar exists — the mismatch shows up as warping (a bimetallic strip) or cracking.

What is the coefficient of thermal expansion?
It is the fractional change in a material’s size per degree of temperature change, written α for linear expansion. Steel’s α ≈ 12×10⁻⁶ /°C means each metre grows about 0.012 mm per degree. Larger α means a material expands more for the same heating.
Are the units per °C or per kelvin?
Either — they are numerically identical. A temperature change of 1 °C is exactly the same size as a change of 1 K, because the Celsius and Kelvin scales share the same degree size. Only the zero point differs, and ΔT cancels the zero point out.
How do area and volume expansion relate to linear expansion?
For small changes, the area coefficient is about 2α and the volume coefficient about 3α. Squaring a length that grew by fraction αΔT roughly doubles the fractional change, and cubing it roughly triples it, which is where the 2 and 3 come from.
Why do bridges have expansion joints?
A long deck can lengthen by centimetres between winter and summer. Expansion joints and sliding bearings let it grow and shrink freely; without them the trapped expansion would generate huge internal forces that could buckle the deck or crack its supports.
What happens when ΔT is negative?
The object contracts. ΔL = α · L₀ · ΔT gives a negative length change when the temperature drops, so the part gets shorter. This is why gaps and joints must accommodate shrinkage in the cold as well as growth in the heat.
Why does Invar barely expand?
Invar is a nickel–iron alloy engineered so its magnetic properties offset normal thermal expansion, giving α ≈ 1.2×10⁻⁶ /°C — roughly a tenth of steel. That stability makes it valuable for precision instruments, clock pendulums, and measuring tools.
Does the original length have to be in metres?
No — α is a pure fractional rate, so any consistent length unit works and ΔL comes out in that same unit. This tool uses metres for L₀ and reports ΔL in millimetres, but the fractional stretch αΔT is unit-free.