Skip to content
K Knidox Search…
Electronics · Components

Capacitors in Series & Parallel

Add capacitors in parallel or combine reciprocals in series — total capacitance, with the steps.

Configuration
UnitCapacitance unit for your values and the result.
Enter positive values separated by commas or spaces.
Try an example
Total capacitance
79µF

3 capacitors in parallel.

Capacitors are the mirror image of resistors. In parallel they add: 10 + 22 + 47 = 79 µF. In series you sum the reciprocals and invert — three 10 µF caps give 1 ÷ (1/10 + 1/10 + 1/10) = 1 ÷ (3/10) = 3.333 µF. Parallel raises capacitance; series lowers it.

Series vs parallel capacitance

How capacitors combine depends on how they are wired — and it is exactly backwards from resistors. In a parallel bank every capacitor shares the same voltage, so their stored charge adds and the capacitances add directly. In a series string the same charge sits on each capacitor while the voltage divides across them, so it is the reciprocals (1/C) that add, then you invert. Parallel gives you more total capacitance; series gives you less.

Parallel: C = ΣC  ·  Series: 1/C = Σ(1/C)

Parallel capacitances add directly; series reciprocals (1/C) add, then invert for C.

Worked example

Combine three 10 µF capacitors in series:

  1. 1
    Pick the wiring. Parallel → add capacitances. Series → add reciprocals, then invert. Here the three caps are in series.
  2. 2
    Sum the reciprocals. 1/C = 1/10 + 1/10 + 1/10 = 3/10 per microfarad.
  3. 3
    Invert to get C. C = 1 ÷ (3/10) = 10/3 ≈ 3.333 µF.
  4. 4
    Sanity-check. n equal capacitors in series give C ÷ n = 10 ÷ 3 ≈ 3.333 µF — smaller than any single cap, as series always is.

Capacitors vs resistors at a glance

Capacitors combine the opposite way to resistors. Series lowers capacitance; parallel raises it.

PropertySeriesParallel
Total capacitance1/C = 1/C₁ + 1/C₂ + ⋯C = C₁ + C₂ + ⋯
Two capacitorsC = C₁C₂ ÷ (C₁ + C₂)C = C₁ + C₂
Shared quantitySame charge on eachSame voltage across each
Total vs eachSmaller than the smallest capLarger than any single cap
Resistors do the...opposite (resistors add)opposite (resistors take reciprocals)

Why capacitors are the opposite of resistors

Capacitance is proportional to plate area. Wiring capacitors in parallel is electrically like widening the plates — more area means more charge stored per volt, so the capacitances add, just as parallel resistors would instead halve resistance. Put capacitors in series and you effectively stack the dielectric gaps, increasing the spacing between the outer plates; wider spacing means less capacitance, so the series total drops below the smallest capacitor. Resistance depends on length rather than area, which is why the two components behave in mirror image.

Do capacitors add in series or in parallel?
Capacitors add in parallel: C = C₁ + C₂ + ⋯. In series the reciprocals add and you invert: 1/C = 1/C₁ + 1/C₂ + ⋯. With 10, 22 and 47 µF that is 79 µF in parallel and about 6.00 µF in series.
Why are capacitors opposite to resistors?
Capacitance is proportional to plate area, so joining capacitors in parallel is like widening the plates — the values add. Resistance depends on length, so parallel resistors instead take reciprocals. The two components mirror each other because area and length scale a circuit in opposite directions.
What do two equal capacitors in series make?
Exactly half of one. Two 10 µF caps in series give 1 ÷ (1/10 + 1/10) = 1 ÷ (2/10) = 5 µF. In general, n equal capacitors in series give C ÷ n, while the same n in parallel give n × C.
Why is a series total smaller than the smallest capacitor?
Series stacks the dielectric gaps, widening the effective spacing between the outer plates, and wider spacing stores less charge per volt. Summing reciprocals can only grow, so its inverse can only shrink — the total sits below the smallest capacitor in the string.
Is there a shortcut for two capacitors in series?
Yes — product over sum: C = C₁C₂ ÷ (C₁ + C₂). For 22 µF and 47 µF that is (22 × 47) ÷ (22 + 47) = 1034 ÷ 69 ≈ 14.99 µF. It works for exactly two; with three or more, sum every reciprocal instead.
Does the unit I choose change the answer?
No — the combination formulas are unit-neutral, so if you enter values in µF the total comes back in µF. Just keep every value in the same unit; mixing µF with nF without converting will skew the result by powers of ten.