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Electronics · Components

Capacitor Energy Calculator

Energy and charge stored in a capacitor from its capacitance and voltage.

The capacitor’s value.
UnitPrefix for the capacitance.
V
Volts across the capacitor.
Try a component
Energy stored (E)
72 mJ

Exact: 0.072 J from E = ½ × C × V².

Charge (Q)
12 mC
0.012 C
Capacitance
1.000e-3 F
1000 µF at 12 V
Energy vs voltage — it grows with the square of voltage
Stored energy E = ½ C V² rising as a parabola with voltage — doubling the voltage quadruples the energy72 mJ00 V12 V

A capacitor stores energy E = ½ × C × V² (joules) and charge Q = C × V (coulombs). A 1000 µF capacitor at 12 V holds Q = 0.001 × 12 = 0.012 C (12 mC) and E = ½ × 0.001 × 12² = 0.072 J (72 mJ). Because energy scales with V², doubling the voltage quadruples it.

What a capacitor stores

A capacitor holds energy in the electric field between its plates. Two quantities describe that store: the charge Q, in coulombs, which is how much electric charge sits on the plates, and the energy E, in joules, which is the work done to move that charge across the plate voltage. Charge grows linearly with voltage, but energy grows with the square of it, so a small rise in voltage stores disproportionately more energy.

E = ½ × C × V²

energy in joules; charge is Q = C × V in coulombs (C in farads, V in volts)

Worked example

A 1000 µF electrolytic capacitor charged to 12 V.

  1. 1
    Convert capacitance to farads. 1000 µF = 1000 × 10⁻⁶ = 1.0 × 10⁻³ F (0.001 F).
  2. 2
    Find the charge (Q = C × V). Q = 0.001 × 12 = 0.012 C, which is 12 mC.
  3. 3
    Square the voltage. V² = 12² = 144 volts squared.
  4. 4
    Apply E = ½ × C × V². E = ½ × 0.001 × 144 = 0.072 J, which is 72 mJ.

Capacitance unit prefixes

How each prefix converts to farads, the SI base unit of capacitance.

UnitNameIn farads
Ffarad1 F
mFmillifarad10⁻³ F = 0.001 F
µFmicrofarad10⁻⁶ F
nFnanofarad10⁻⁹ F
pFpicofarad10⁻¹² F

Why voltage matters most, and staying safe

Energy scales with V², not V. Because the V² term dominates, doubling the voltage on the same capacitor quadruples the stored energy, while doubling the capacitance only doubles it. Voltage is the lever with the biggest effect — and the reason a capacitor’s voltage rating is chosen with margin.

Charged capacitors bite. A large electrolytic or a high-voltage capacitor can hold a dangerous charge long after power is removed, because there is often no path to discharge it. Before touching a circuit, discharge big capacitors through a suitable resistor (never a bare screwdriver, which arcs and can damage the part) and confirm the voltage has fallen to zero.

Why does capacitor energy depend on V squared?
As a capacitor charges, its voltage rises from 0 to V, so the average voltage the charge crosses is V÷2. Energy is charge × average voltage = (C·V) × (V÷2) = ½CV², which is why doubling voltage quadruples the stored energy.
What is the difference between charge and energy?
Charge Q = C × V (coulombs) is how much electric charge sits on the plates and rises linearly with voltage. Energy E = ½CV² (joules) is the work stored in the field and rises with the square of voltage.
µF vs nF vs pF — how do they compare?
They are steps of a thousand: 1 µF = 1000 nF = 1,000,000 pF. A microfarad (10⁻⁶ F) is typical of electrolytics, nanofarads (10⁻⁹ F) of decoupling caps, and picofarads (10⁻¹² F) of small ceramics in RF and timing circuits.
What units should I put in the formula?
Use capacitance in farads and voltage in volts; the result is then in joules. Convert prefixed values first — for example 100 nF becomes 100 × 10⁻⁹ = 1.0 × 10⁻⁷ F. The tool’s unit selector does this conversion for you.
How much energy does a 1000 µF cap hold at 12 V?
E = ½ × 0.001 F × 12² = 0.072 J, or 72 mJ, and it carries a charge of Q = 0.001 × 12 = 0.012 C (12 mC). Raising it to 24 V would store four times as much: 0.288 J.
Does a bigger capacitor always store more energy?
Not necessarily. Energy is ½CV², so a small capacitor at high voltage can beat a large one at low voltage. A 1 µF cap at 400 V stores 0.08 J, more than a 1000 µF cap at 12 V (0.072 J).