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Chemistry · Electrochemistry

Nernst Equation Calculator

Find a cell’s potential under non-standard conditions from E°, the electrons transferred, the reaction quotient, and temperature.

V
Standard cell potential in volts.
Moles of electrons in the balanced reaction.
Products over reactants at that instant.
K
Absolute temperature in kelvin.
Try a cell
Cell potential (E)
1.1 V

Correction term (E − E°): +0 V from the RT ÷ nF · ln Q shift.

Cell potential vs reaction quotient Q (E = E° at Q = 1)
Cell potential E decreasing as the reaction quotient Q rises, crossing E° at Q = 11.159 V1.041 VQ = 0.01Q = 100

The Nernst equation gives cell potential away from standard state: E = E° − (RT ÷ nF) ln Q. For a Daniell cell (E° = 1.10 V, n = 2) at 25 °C with Q = 10, E = 1.10 − (0.05916 ÷ 2) × 1 = 1.070 V. When Q = 1 the log term is zero, so E = E°.

What the Nernst equation does

Standard cell potentials (E°) assume every species is at 1 M concentration or 1 bar pressure. Real cells rarely sit at those conditions, and as a battery runs the concentrations shift. The Nernst equation corrects E° for the actual mix of reactants and products, captured by the reaction quotient Q, and for temperature T. The correction is the term −(RT ÷ nF) ln Q: it is zero at standard state (Q = 1), positive when reactants dominate (Q < 1), and negative once products build up (Q > 1).

E = E° − (R·T ÷ n·F) ln Q

R = 8.314 J·mol⁻¹·K⁻¹, F = 96485 C/mol, n = electrons transferred; at 25 °C this becomes E = E° − (0.05916 ÷ n) log₁₀ Q

Worked example

A Daniell cell has E° = 1.10 V and transfers n = 2 electrons. It runs until the reaction quotient reaches Q = 10, at 298.15 K (25 °C).

  1. 1
    Gather E°, n, Q, and T. Here E° = 1.10 V, n = 2, Q = 10, T = 298.15 K. Q is products over reactants, each raised to its coefficient.
  2. 2
    Pick the right form. At 25 °C the RT ÷ F factor collapses to 0.05916 V, so E = E° − (0.05916 ÷ n) log₁₀ Q. For any other temperature keep the full RT ÷ nF · ln Q term.
  3. 3
    Compute the correction. (0.05916 ÷ 2) × log₁₀(10) = 0.02958 × 1 = 0.02958 V.
  4. 4
    Subtract from E°. E = 1.10 − 0.02958 = 1.070 V. Because Q > 1, products have accumulated and E has dropped below E°.

How Q shifts the potential (n = 1, 25 °C)

Each tenfold change in Q moves a one-electron cell by 0.05916 V; divide by n for multi-electron cells.

Reaction quotient Qlog₁₀ QPotential shift (E − E°)
0.1−1+0.0592 V
100 V
10+1−0.0592 V

What happens as the cell runs

A working cell consumes reactants and makes products, so Q climbs from its starting value toward the equilibrium constant K. Each rise in Q pushes the −(RT ÷ nF) ln Q term more negative, so E falls steadily. When Q finally equals K the cell reaches equilibrium, the correction exactly cancels E°, and E = 0 — the battery is dead. Reading it backward, the Nernst equation also links E° to K: at equilibrium 0 = E° − (RT ÷ nF) ln K.

What is the reaction quotient Q?
Q has the same product-over-reactant form as the equilibrium constant, each concentration or pressure raised to its stoichiometric coefficient, but evaluated at the current instant rather than at equilibrium. Pure solids and liquids are omitted. At standard state Q = 1, so ln Q = 0 and E = E°.
Why does E drop as the cell runs?
As reactants convert to products, Q increases, which makes the −(RT ÷ nF) ln Q correction more negative and lowers E. The cell keeps discharging until Q reaches the equilibrium constant K, at which point E = 0 and no more useful work can be drawn.
Where does the 0.05916 come from?
It is (RT ÷ F) × ln 10 evaluated at 298.15 K: (8.314 × 298.15 ÷ 96485) × 2.302585 ≈ 0.05916 V. It converts the natural-log form to a base-10 form, which is why the shortcut only holds at 25 °C — at other temperatures use the full RT ÷ nF · ln Q expression.
How does n change the result?
n is the number of electrons transferred in the balanced redox reaction. It sits in the denominator, so a larger n makes the potential less sensitive to concentration: doubling n from 1 to 2 halves each 0.05916 V shift to 0.02958 V per tenfold change in Q.
Does temperature matter much?
The correction scales linearly with T through RT ÷ nF, so it grows as the cell warms. The effect is modest near room temperature but real: this calculator uses the full RT ÷ nF form, so any T you enter is handled exactly rather than assuming 25 °C.
Can I use the Nernst equation for a single half-cell?
Yes. Applied to one electrode it gives that half-cell’s potential relative to the standard hydrogen electrode, using the half-reaction’s own n and its Q built from the ion activities involved. Subtracting the anode value from the cathode value rebuilds the full cell potential.