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Chemistry · Equilibrium

Equilibrium Constant (K)

Compute K from the equilibrium concentrations and coefficients of a reversible reaction.

aA + bB ⇌ cC + dD

A · reactant
mol/L
B · reactant
mol/L
C · product
mol/L
D · product
mol/L

Leave a concentration or coefficient at 0 to drop that slot (it counts as a factor of 1).

K (equilibrium constant)
4Favors products

Concentration-based Kc. K is dimensionless by the standard-state convention.

For the reaction aA + bB ⇌ cC + dD, the equilibrium constant is K = ([C]ᶜ · [D]ᵈ) ÷ ([A]ᵃ · [B]ᵇ), using equilibrium concentrations in mol/L. With [A] = [B] = 0.5 mol/L, [C] = [D] = 1.0 mol/L and all coefficients 1, K = (1 · 1) ÷ (0.5 · 0.5) = 4.

What the equilibrium constant tells you

At equilibrium a reversible reaction stops changing on the macroscopic scale: the forward and reverse rates are equal and the concentrations hold steady. The equilibrium constant K captures that steady balance as a single number — the ratio of product concentrations to reactant concentrations, each raised to its stoichiometric coefficient. A large K means the position of equilibrium lies far toward the products; a small K means reactants dominate.

K = ([C]ᶜ · [D]ᵈ) ÷ ([A]ᵃ · [B]ᵇ)

Concentrations in mol/L at equilibrium; exponents are the balanced coefficients

Worked example

A reaction A + B ⇌ C + D reaches equilibrium with [A] = [B] = 0.5 mol/L and [C] = [D] = 1.0 mol/L. All coefficients are 1.

  1. 1
    Write the balanced equation. A + B ⇌ C + D, so every coefficient (a, b, c, d) is 1.
  2. 2
    Build the K expression. Products over reactants, each raised to its coefficient: K = ([C]¹ · [D]¹) ÷ ([A]¹ · [B]¹).
  3. 3
    Substitute equilibrium concentrations. K = (1.0 · 1.0) ÷ (0.5 · 0.5) = 1 ÷ 0.25.
  4. 4
    Evaluate. K = 4. Because K > 1, the equilibrium favors the products.

Reading the value of K

K compares products to reactants at equilibrium; the thresholds are guidelines, not hard cut-offs.

Value of KPosition of equilibriumInterpretation
K ≫ 1Far toward productsReaction goes nearly to completion
K ≈ 1BalancedComparable amounts of reactants and products
K ≪ 1Far toward reactantsLittle product forms

Kc, Kp, and what gets left out

Kc vs Kp. This calculator computes Kc from molar concentrations. For gas-phase reactions you can instead use Kp, built from partial pressures; the two are related by Kp = Kc(RT)Δn, where Δn is the change in moles of gas.

Pure solids and liquids are omitted. Their “concentration” doesn’t change as the reaction proceeds, so by convention they’re assigned an activity of 1 and dropped from the expression — only gases and dissolved (aqueous) species appear.

Units convention. Strictly, K is built from dimensionless activities (each concentration divided by the 1 mol/L standard state), so K itself carries no units. The calculator follows this convention and reports K as a pure number.

What does the equilibrium constant K actually mean?
K is the ratio of product concentrations to reactant concentrations at equilibrium, each raised to its balanced coefficient. It fixes the position of equilibrium for a reaction at a given temperature.
What’s the difference between a large and a small K?
A large K (≫ 1) means equilibrium lies far toward the products — the reaction goes nearly to completion. A small K (≪ 1) means reactants dominate and little product forms. K ≈ 1 means comparable amounts of each.
Why are pure solids and liquids left out of the expression?
Their effective concentration (activity) stays constant as the reaction proceeds, so by convention it’s set to 1 and they drop out. Only gases and aqueous species appear in K.
What’s the difference between Kc and Kp?
Kc is built from molar concentrations; Kp from partial pressures of gases. They’re linked by Kp = Kc(RT)^Δn, where Δn is the change in moles of gas. This tool computes Kc.
Does K change if I add more reactant?
No. K depends only on temperature. Changing a concentration shifts the system to re-establish equilibrium, but the ratio K stays the same. Only a temperature change alters K.
Does K have units?
By the standard-state convention K is dimensionless, because each concentration is divided by the 1 mol/L reference state before the ratio is formed. This calculator reports K as a pure number.