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Biology · Sequence tools

Protein Molecular Weight

Molecular weight from an amino acid sequence, with composition and the A280 extinction coefficient.

One-letter codes. FASTA headers, spaces, line breaks and numbering are ignored.
Average molecular weight
2,383.71Da

21 residues · 2.384 kDa

Residues
21
ε at 280 nm
2,980 M⁻¹cm⁻¹
A280 of 1 mg/mL
1.250
Composition
N
2 · 10%
C
4 · 19%
E
2 · 10%
Q
2 · 10%
G
1 · 5%
I
2 · 10%
L
2 · 10%
S
2 · 10%
T
1 · 5%
Y
2 · 10%
V
1 · 5%

A protein’s molecular weight is the sum of its residue masses plus one water molecule for the free ends. The insulin A chain, GIVEQCCTSICSLYQLENYCN, comes to 2383.71 Da — 21 residues at an average of about 110 Da each, which is the rule of thumb behind “roughly 110 Da per residue”.

Residue mass, not amino acid mass

Free alanine weighs 89.09 Da, but inside a chain it contributes only 71.08. The difference is a water molecule: forming each peptide bond releases one, so a residue is the amino acid minus H₂O. Summing residue masses and adding a single water back at the end accounts for the two free termini and gives the mass of the whole chain.

That is why a protein of n residues has n − 1 peptide bonds and loses n − 1 waters. Adding one water at the end, rather than none or n, is the step most hand calculations get wrong.

Average against monoisotopic

The masses here are average masses, weighted across the natural isotope abundances, and they are what SDS-PAGE, size-exclusion chromatography and everyday lab work use. Mass spectrometry with enough resolution instead reports monoisotopic mass, computed from the most abundant isotope of each element only. For a small peptide the two differ by around a dalton; for a large protein the gap grows to tens of daltons, so quoting the wrong one in a mass spec context is a real error.

MW = Σ residue masses + 18.015 Da

one water for the free amino and carboxyl termini; average masses, not monoisotopic

  1. 1
    Write the sequence in one-letter code. The insulin A chain is GIVEQCCTSICSLYQLENYCN — 21 residues.
  2. 2
    Look up the residue mass of each letter. Glycine is 57.05, isoleucine 113.16, valine 99.13, and so on.
  3. 3
    Add them all together. The twenty-one residues sum to 2365.69 Da.
  4. 4
    Add one water. 2365.69 + 18.02 = 2383.71 Da, or about 2.38 kDa.
  5. 5
    Sanity-check against 110 Da per residue. 21 × 110 ≈ 2310, close enough to confirm no residue was miscounted.

Residue masses at the extremes

In daltons. The spread is why composition matters and a residue count alone is only an estimate.

ResidueOne-letterMass
Glycine — the smallestG57.05 Da
AlanineA71.08 Da
Average across the twenty—≈ 110 Da
ArginineR156.19 Da
TyrosineY163.18 Da
Tryptophan — the largestW186.21 Da

Why the extinction coefficient comes with it

Proteins absorb at 280 nm almost entirely because of their tryptophan and tyrosine residues, so the molar extinction coefficient can be predicted from composition: 5500 M⁻¹cm⁻¹ for each Trp and 1490 for each Tyr, following Pace’s coefficients. Dividing that by the molecular weight gives the absorbance of a 1 mg/mL solution, which is what turns a spectrophotometer reading into a concentration.

Two caveats. The figure here assumes all cysteines are reduced; disulfide bonds add about 125 M⁻¹cm⁻¹ per cystine and each one also removes two hydrogens from the mass. And a protein with no tryptophan or tyrosine has an extinction coefficient near zero, so A280 cannot measure it at all — a Bradford or BCA assay is needed instead. Post-translational modifications, signal peptide cleavage and bound cofactors all shift the real mass away from what the sequence alone predicts.

Why add a water molecule at the end?
Because each peptide bond releases one. A chain of n residues has n − 1 bonds, so summing residue masses undercounts by exactly one water — the one that makes up the free amino and carboxyl termini.
What is the difference between residue mass and amino acid mass?
A residue is the amino acid minus a water molecule, which is what it actually contributes inside a chain. Free alanine is 89.09 Da; as a residue it is 71.08 Da.
Why is 110 Da per residue a useful estimate?
Because it is roughly the average residue mass weighted by how often each amino acid occurs. Multiplying residue count by 110 gets within a few percent, which is enough to check a calculation or read a gel.
What is the difference between average and monoisotopic mass?
Average mass weights each element across its natural isotopes and is what gels and chromatography report. Monoisotopic mass uses only the most abundant isotope of each element and is what high-resolution mass spectrometry measures; the two diverge as the protein gets larger.
How is the extinction coefficient calculated?
From tryptophan and tyrosine content: 5500 M⁻¹cm⁻¹ per Trp plus 1490 per Tyr. Dividing by the molecular weight gives the A280 of a 1 mg/mL solution, which converts a spectrophotometer reading into a concentration.
Why does my measured mass differ from the calculated one?
Usually post-translational modification. Glycosylation, phosphorylation, signal peptide cleavage, disulfide formation and bound cofactors all change the real mass, and none of them appear in the amino acid sequence.
Can I measure any protein at 280 nm?
Only if it contains tryptophan or tyrosine. A protein with neither has an extinction coefficient near zero at that wavelength, and its concentration has to be measured by a Bradford or BCA assay instead.