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Statistics · Probability

Probability Calculator

Find the chance of a single event, of two independent events both or either happening, or of at least one success across several trials.

What are you calculating?
Outcomes that count as a success.
All equally likely outcomes.
Probability
16.67%1⁄6

1 favorable out of 6 equally likely outcomes

Try an example

Probability is favorable outcomes ÷ total equally likely outcomes, so rolling one specific number on a die is 1 ÷ 6 ≈ 0.1667 = 16.7%. For two independent events both happening, multiply: P(A and B) = P(A) × P(B). Two coins both landing heads is ½ × ½ = 0.25 = 25%.

What probability measures

Probability is a number from 0 to 1 that scores how likely an event is: 0 means it never happens, 1 means it always happens, and 0.5 is an even chance. When every outcome is equally likely, you get it by counting — divide the outcomes you care about by the total number of outcomes. The same value can be written three ways: a fraction (1⁄6), a decimal (0.1667), or a percent (16.67%). Combining events is where it gets interesting: whether you multiply or add depends on whether you want both events, either event, or none of them.

P(event) = favorable outcomes ÷ total outcomes

valid only when every outcome is equally likely

Worked example

What is the chance of getting at least one six when you roll a fair die four times?

  1. 1
    Find the single-event probability. One six out of six faces: P(six) = 1 ÷ 6 ≈ 0.1667.
  2. 2
    Flip to the complement. The chance of not rolling a six on one roll is 1 − 1⁄6 = 5⁄6 ≈ 0.8333.
  3. 3
    Multiply across the independent trials. No six in all four rolls: (5⁄6)⁴ ≈ 0.4823.
  4. 4
    Subtract from 1. P(at least one six) = 1 − 0.4823 = 0.5177 ≈ 51.8%.

Combining events

Formulas for independent events A and B with probabilities P(A) and P(B).

You wantFormulaReads as
Both (A and B)P(A) × P(B)A happens and B also happens
Either (A or B)P(A) + P(B) − P(A) × P(B)at least one of A or B happens
Neither(1 − P(A)) × (1 − P(B))A fails and B fails
At least one in n trials1 − (1 − p)ⁿsuccess on one or more of n attempts

Independent vs. mutually exclusive — and the complement trick

Independent events don’t affect each other, so their joint probability multiplies: two coin flips, or rolls of separate dice. Mutually exclusive events can’t both occur in a single trial — rolling a 2 and a 5 on one die — so for “either” you simply add, because the overlap term P(A and B) is zero. Mixing these up is the most common probability mistake: only add raw probabilities when the events truly cannot co-occur.

The complement trick turns awkward “at least one” questions into easy ones. Instead of adding up the chances of exactly one, exactly two, and so on, compute the one case you’re trying to avoid — zero successes — and subtract from 1. That is why P(at least one) = 1 − (1 − p)ⁿ: (1 − p)ⁿ is the chance every trial fails, and everything else is “at least one.”

What’s the difference between independent and mutually exclusive events?
Independent events don’t influence each other’s outcome, so you multiply their probabilities for “both.” Mutually exclusive events cannot happen together in the same trial, so they can’t be independent — for those, “either” is just P(A) + P(B).
When do I multiply and when do I add probabilities?
Multiply for “and” (both events happening): P(A) × P(B) for independent events. Add for “or” (at least one), but subtract the overlap to avoid double-counting: P(A) + P(B) − P(A) × P(B).
What is the complement rule?
The probability that an event does not happen is 1 minus the probability that it does: P(not A) = 1 − P(A). It’s the fastest route to many answers, especially “at least one” problems.
How do I find the chance of “at least one” success?
Use the complement: P(at least one) = 1 − (1 − p)ⁿ, where p is the per-trial probability and n is the number of independent trials. For at least one six in four rolls, 1 − (5⁄6)⁴ ≈ 0.5177.
What’s the difference between odds and probability?
Probability compares favorable outcomes to all outcomes (1 in 6). Odds compare favorable to unfavorable (1 to 5). Convert with probability = odds ÷ (odds + 1); 1-to-5 odds give 1⁄6 ≈ 0.167.
Can a probability be greater than 1 or negative?
No. Every probability lies between 0 and 1 (0% to 100%). If a calculation lands outside that range, you’ve likely added overlapping events without subtracting the “and” term, or double-counted an outcome.