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Physics · Mechanics

Gravitational Force Calculator (Newton’s Law)

Compute the attraction between two masses with F = G·m₁m₂ ÷ r².

kg
kg
m
Gravitational force (F)
687.367N

G = 6.674×10⁻¹¹ N·m²/kg². Enter masses in kg and distance in metres; use e-notation for large values (e.g. 5.972e24).

Force vs separation — it falls with the inverse square of distance
Gravitational force falling off with the inverse square of separation — doubling the distance quarters the force2749.47 N171.842 N3.1855e+6 m1.2742e+7 m

Newton’s law of universal gravitation is F = G·m₁m₂ ÷ r², with G = 6.674×10⁻¹¹ N·m²/kg². For Earth (m₁ = 5.972×10²⁴ kg) and a 70 kg person at Earth’s radius (r = 6.371×10⁶ m), F ≈ 687 N — which is exactly that person’s weight.

Newton’s law of universal gravitation

Every pair of masses attracts along the line joining them with a force proportional to the product of the masses and inversely proportional to the square of the distance between their centres: F = G·m₁m₂ ÷ r². The force is mutual — Earth pulls you down with the same strength you pull Earth up. Because gravity always attracts, this is also what the F = ma calculator reports as your weight when you stand on the ground.

F = G · m₁m₂ ÷ r²

G = 6.674×10⁻¹¹ N·m²/kg², m₁ & m₂ in kg, r in metres, F in newtons (N)

Worked example

How hard does Earth pull on a 70 kg person standing at sea level? Use m₁ = 5.972×10²⁴ kg, m₂ = 70 kg, and r = 6.371×10⁶ m (Earth’s mean radius).

  1. 1
    Write Newton’s law. F = G·m₁m₂ ÷ r², with G = 6.674×10⁻¹¹ N·m²/kg².
  2. 2
    Substitute the values. F = 6.674×10⁻¹¹ × (5.972×10²⁴) × 70 ÷ (6.371×10⁶)².
  3. 3
    Square the distance. r² = (6.371×10⁶)² ≈ 4.059×10¹³ m².
  4. 4
    Compute the force. F ≈ 687 N — equal to the person’s weight, since this gravitational pull is what we call weight.

Key values and the inverse-square rule

G is fixed; the force scales with 1 ÷ r², so distance dominates.

QuantityValue / effectUnit
Gravitational constant G6.674×10⁻¹¹N·m²/kg²
Earth’s mass5.972×10²⁴kg
Earth’s mean radius6.371×10⁶m
Double the distance (r → 2r)Force × ¼ (quarters)
Triple the distance (r → 3r)Force × 1⁄9

The inverse-square law and why gravity feels one-sided

Distance dominates. Because F depends on 1 ÷ r², doubling the separation cuts the force to a quarter and tripling it to a ninth. This is why gravity reaches across space yet fades quickly — orbits, tides, and the strength of g all trace back to that r² in the denominator.

Why everyday objects barely attract. G is minuscule (6.674×10⁻¹¹), so two 1 kg masses one metre apart attract with only about 6.7×10⁻¹¹ N — far too weak to feel. Gravity only becomes obvious when one of the masses is enormous, like a planet.

Link to g. Dividing the formula by the small mass gives the field strength g = G·M ÷ r². With Earth’s mass and radius this yields g ≈ 9.81 m/s², so weight W = m·g is just F = G·m₁m₂ ÷ r² rewritten for one big body.

What is the gravitational constant G?
G is the universal constant of gravitation, 6.674×10⁻¹¹ N·m²/kg². It sets the absolute strength of gravity and is the same everywhere in the universe — only the masses and distance change between problems.
What does the inverse-square law mean?
The force is proportional to 1 ÷ r², so it falls off with the square of the distance. Double the separation and the pull drops to one quarter; triple it and the pull drops to one ninth.
Why don’t we feel the gravitational pull toward everyday objects?
Because G is so tiny, ordinary masses attract negligibly — two 1 kg masses a metre apart pull with about 6.7×10⁻¹¹ N. Gravity is only noticeable when one mass is astronomically large, like a planet or star.
How is gravitational force related to weight?
Your weight is the gravitational force between you and Earth. For a 70 kg person at Earth’s radius, F = G·m₁m₂ ÷ r² ≈ 687 N, which matches W = m·g = 70 × 9.81 N.
How does this relate to g = GM ÷ r²?
Divide F = G·m₁m₂ ÷ r² by your own mass and you get the field strength g = G·M ÷ r². Using Earth’s mass and radius gives g ≈ 9.81 m/s², the familiar acceleration of free fall.
What units does the calculator use?
SI units: masses in kilograms, distance in metres, and the resulting force in newtons. Enter very large or very small numbers in e-notation, e.g. 5.972e24 for Earth’s mass.