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Math · Algebra

Synthetic Division Calculator

Divide a polynomial by (x − c) using only its coefficients.

Comma- or space-separated. Use a 0 for any missing term.
The root you are testing.
Try an example
Quotient of dividing by (x − 3)
x² + x − 1Factor

Remainder: 0. Since the remainder is 0, (x − 3) divides evenly, so it is a factor and x = 3 is a root.

31-2-43
33-3
11-10

Top row: coefficients. Middle row: each result × 3. Bottom row: the sums — the last one (in colour) is the remainder, the rest are the quotient.

Synthetic division divides a polynomial by a linear factor (x − c) using just its coefficients. Dividing x³ − 2x² − 4x + 3 by (x − 3) gives a quotient of x² + x − 1 with a remainder of 0. A remainder of 0 means (x − 3) is a factor and x = 3 is a root.

What synthetic division does

Synthetic division is a shorthand for dividing a polynomial by a linear divisor of the form (x − c). Instead of writing out full long division, you work with only the coefficients: bring the first one down, then repeatedly multiply by c and add. The final number is the remainder, and the numbers before it are the coefficients of the quotient — a polynomial one degree lower than the one you started with.

Worked example

Divide x³ − 2x² − 4x + 3 by (x − 3), so c = 3:

  1. 1
    Write the coefficients in order. For x³ − 2x² − 4x + 3, list 1, −2, −4, 3 from the highest power down. Insert a 0 for any missing term. Put c = 3 to the left.
  2. 2
    Bring down the first coefficient. Copy the leading 1 straight down to start the bottom row.
  3. 3
    Multiply by c, then add. 1 × 3 = 3; add to −2 to get 1. Then 1 × 3 = 3; add to −4 to get −1. Then −1 × 3 = −3; add to 3 to get 0.
  4. 4
    Read off the answer. The bottom row is 1, 1, −1, 0. The last number, 0, is the remainder; the rest are the quotient x² + x − 1.

The synthetic-division process

Work left to right across the coefficients. The single number left over at the end is the remainder.

PositionOperationMeaning
First coefficientBring it straight downStarts the quotient
Each next columnMultiply the last result by cGives the number to add
Same columnAdd it to the coefficient aboveThe next quotient coefficient
RepeatCarry down to the last columnOne column per coefficient
Last numberNothing follows itThis is the remainder = P(c)

Reading the result

It only works for a linear divisor. Synthetic division is a shortcut specifically for dividing by (x − c). To divide by something like (x² + 1) or (2x − 3) written as a general polynomial, use polynomial long division instead — although 2x − 3 can be handled by dividing by (x − 3/2) and scaling.

The remainder equals P(c). By the Remainder Theorem, dividing P(x) by (x − c) leaves a remainder of exactly P(c). In the example, P(3) = 27 − 18 − 12 + 3 = 0, which matches the remainder from the table.

A remainder of 0 means a factor. When the remainder is 0, (x − c) divides P(x) evenly, so (x − c) is a factor and x = c is a root. That is why synthetic division is a fast way to test candidate roots and to peel factors off a polynomial one at a time.

When can I use synthetic division?
Only when the divisor is linear and monic — that is, of the form (x − c). For any other divisor, such as (x² − 1) or a quadratic, use polynomial long division instead.
What does a remainder of zero mean?
It means (x − c) divides the polynomial exactly, so (x − c) is a factor and x = c is a root. A non-zero remainder means it is not a factor.
How do I handle a missing term?
Insert a 0 for its coefficient so every power is represented. For x³ − 4 you enter 1, 0, 0, −4 — the missing x² and x terms become zeros.
What sign of c do I use for (x + 2)?
Rewrite (x + 2) as (x − (−2)), so c = −2. Always take c as the value that makes the divisor zero; for (x − 3) that is c = 3.
How does the remainder relate to P(c)?
By the Remainder Theorem they are equal: dividing P(x) by (x − c) leaves a remainder of exactly P(c). This makes synthetic division a quick way to evaluate a polynomial at c.
What degree is the quotient?
Exactly one less than the dividend. Dividing a cubic (degree 3) by a linear factor gives a quadratic (degree 2) quotient, plus a constant remainder.