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Half-Life Calculator

Find how much of a decaying substance remains after a given time.

Starting quantity before any decay.
Time for the amount to halve. Use the same units as elapsed time.
How much time has passed, in the same units as the half-life.
Isotopes — tap to load
Remaining amount (N)
12.5

3 half-lives elapsed · 12.5% remaining

Decay over time
Remaining amount decaying over time10013t = 0t = 15

With a half-life of 5 units, a 100-unit sample loses half its amount every 5 units of time. After 15 units, that’s 15 ÷ 5 = 3 half-lives, so the amount halves three times: 100 → 50 → 25 → 12.5. So 12.5 units (12.5%) remain.

What a half-life is

A half-life (t½) is the time it takes for half of a decaying substance to disappear. After one half-life half remains, after two half-lives a quarter remains, after three an eighth — the amount falls by the same factor of ½ over each equal interval, which is what makes the decay exponential rather than linear.

N = N₀ × (½)^(t ÷ t½)

N₀ = initial amount · t = elapsed time · t½ = half-life (t and t½ in the same units)

Worked example

How much of a 100-unit sample remains after 15 units of time, given a half-life of 5 units?

  1. 1
    Count the half-lives elapsed. Divide elapsed time by the half-life: n = t ÷ t½ = 15 ÷ 5 = 3.
  2. 2
    Apply the decay law. N = N₀ × (½)ⁿ = 100 × (½)³ = 100 × ⅛.
  3. 3
    Compute the remaining amount. N = 100 × 0.125 = 12.5 units — that’s 12.5% of the original sample left.

Fraction remaining after each half-life

Each half-life multiplies the remaining amount by ½.

Half-lives elapsedFraction remainingPercent remaining
1½50%
2¼25%
312.5%
41⁄166.25%
51⁄323.125%

Reading the result

It never truly reaches zero. Exponential decay always leaves some fraction behind — after 10 half-lives roughly 0.1% remains, after 20 about a millionth. In practice the amount becomes undetectable, but mathematically it only approaches zero.

Units must match. The half-life and the elapsed time must use the same time units. Carbon-14, for instance, has a half-life of about 5730 years, so a 11,460-year-old sample (two half-lives) holds about a quarter of its original carbon-14 — the basis of radiocarbon dating.

The elapsed time need not be a whole number of half-lives. The exponent t ÷ t½ can be fractional; (½) raised to a non-integer power still gives a valid fraction remaining.

What exactly is a half-life?
It’s the time required for half of a decaying quantity to be lost. After one half-life 50% remains, after two 25%, after three 12.5% — the same halving repeats over every equal interval.
Does the substance ever fully decay to zero?
No. Each half-life removes half of what is left, so the amount keeps approaching zero without reaching it. After about 10 half-lives only ≈0.1% remains, which is usually undetectable but not exactly zero.
Do the time and half-life need the same units?
Yes. The exponent is t ÷ t½, so both must be in the same units — seconds with seconds, years with years. Mixing units (for example years with days) gives a wrong number of half-lives.
How is this used in carbon dating?
Carbon-14 decays with a half-life of about 5730 years. Measuring how much carbon-14 is left tells you how many half-lives have passed: a quarter remaining means ≈11,460 years, an eighth means ≈17,190 years.
What fraction remains after n half-lives?
Exactly (½)ⁿ. So after 3 half-lives it is (½)³ = ⅛ = 12.5%, and after 4 it is (½)⁴ = 1⁄16 = 6.25%.
Can the elapsed time be a fraction of a half-life?
Yes. The formula uses (½)^(t ÷ t½) with a continuous exponent, so 2.5 half-lives gives (½)^2.5 ≈ 0.177, or about 17.7% remaining.