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Chemistry · Spectroscopy

Beer-Lambert Law Calculator

Solve A = ε · l · c for absorbance, concentration, molar absorptivity, or path length.

Solve for
In L·mol⁻¹·cm⁻¹.
cm
Cuvette width in cm.
mol/L
In mol/L.
Try a scenario
Absorbance (A)
2

Transmittance: %T = 10^(−A) × 100 = 1% (at A = 2).

Absorbance is proportional to concentration
Absorbance rising in a straight line as concentration increasesA = 200c = 1e-4 mol/L

The Beer-Lambert law states A = ε · l · c: absorbance equals molar absorptivity times path length times concentration. For ε = 20000 L·mol⁻¹·cm⁻¹, l = 1 cm, and c = 1×10⁻⁴ mol/L, A = 20000 × 1 × 0.0001 = 2.0, which corresponds to just 1% transmittance.

What the Beer-Lambert law describes

When light passes through a coloured solution, part of it is absorbed. The Beer-Lambert law links the measured absorbance to how strongly the substance absorbs (its molar absorptivity ε), how far the light travels through the sample (the path length l, usually the 1 cm cuvette), and how concentrated the solution is (c). Because absorbance is directly proportional to concentration, a spectrophotometer reading can be turned into a concentration once ε and l are known.

A = ε · l · c

A absorbance (unitless) · ε molar absorptivity (L·mol⁻¹·cm⁻¹) · l path length (cm) · c concentration (mol/L). Transmittance: A = −log₁₀ T

Worked example

A dye with ε = 20000 L·mol⁻¹·cm⁻¹ is measured in a 1 cm cuvette at a concentration of 1×10⁻⁴ mol/L. What is its absorbance, and how much light gets through?

  1. 1
    Pick the unknown. Choose which of A, ε, l, or c you are solving for; the calculator rearranges A = ε · l · c accordingly.
  2. 2
    Enter the three known values. Here ε = 20000 L·mol⁻¹·cm⁻¹, l = 1 cm, and c = 1×10⁻⁴ mol/L, so A = 20000 × 1 × 0.0001.
  3. 3
    Read the absorbance. A = 2.0. Absorbance has no units — it is the log of the light attenuation.
  4. 4
    Convert to transmittance. T = 10^(−A) = 10⁻² = 0.01, so %T = 1%. Only 1% of the incident light passes through the sample.

Absorbance to transmittance

T = 10^(−A); %T = T × 100. Each unit of absorbance cuts transmitted light by a factor of ten.

Absorbance (A)Transmittance (T)%T
01100%
10.110%
20.011%
30.0010.1%

Where the linear law breaks down

It is only linear at low absorbance. Beer-Lambert holds when absorbance is roughly below 1; most instruments are most accurate between about 0.1 and 1.0. Above that, stray light and detector limits make the reading fall below the true proportional value.

High concentrations cause deviations. At high concentration the molecules interact, the refractive index shifts, and analytes may associate or dissociate — so absorbance stops rising in step with concentration. Diluting the sample back into the linear range restores the straight-line relationship.

ε depends on wavelength and conditions. Molar absorptivity is measured at a specific wavelength (usually the absorption maximum) and can change with solvent, pH, and temperature, so quote it alongside those conditions.

What is molar absorptivity (ε)?
Molar absorptivity, also called the molar extinction coefficient, measures how strongly a substance absorbs light at a given wavelength. Its units are L·mol⁻¹·cm⁻¹, and a larger ε means a more intensely coloured, stronger-absorbing compound.
What is the difference between absorbance and transmittance?
Transmittance T is the fraction of light that passes through the sample (0 to 1, or 0–100% as %T). Absorbance is the logarithm of its inverse: A = −log₁₀ T. Absorbance is proportional to concentration, which is why it, not transmittance, is used in the Beer-Lambert law.
Why is absorbance unitless?
Absorbance is defined as the base-10 log of the ratio of incident to transmitted light intensity (log₁₀ I₀/I). Because it is a ratio of two intensities, the units cancel, leaving a pure number.
What path length should I use?
Use the internal width of the cuvette the light crosses — a standard cuvette is 1 cm, which is why l = 1 is so common. Micro-cuvettes and flow cells can differ, so check the value if your absorbances look off.
How do I find concentration from absorbance?
Rearrange the law to c = A ÷ (ε · l). Measure A, use the known ε at that wavelength and the cuvette path length, and divide. For A = 0.75 with ε = 15000 and l = 1 cm, c = 0.75 ÷ 15000 = 5×10⁻⁵ mol/L.
Why should I keep absorbance below about 1?
The linear relationship weakens at high absorbance because of stray light, molecular interactions, and detector limits. Readings near 2–3 are increasingly unreliable, so dilute the sample until A falls in the accurate 0.1–1.0 range.